Question

Write a quadratic polynomial whose product of the zeroes is -36 and one of the zero is 9.

Answer 1

Answer:

Given:

Product of zeroes =-36...... (1)

Let alpha and beta be the roots of given eq.

Therefore,

Alpha ×beeta=-36.... (from 1)

and it is given that one of the zeros is 9

Therefore, substituting 9 in eq. (1)

we get beeta as -4.

Alpha+beeta=5.... (2)

The required quadratic equation is:

x²-(alpha+beeta) x+alpha×beeta

x²-5x-36=0

Answer 2

Answer:

x^2-9x-36

Step-by-step explanation:

by the relationship between the cofficients and variable

αβ=c/a

α+β=-b/a

given:αβ=-36,α+β = 9

put the value

c= -36 and b=-9 and a=1

equation is x^2-9x-36