Question

Write a quadratic polynomial whose zeroes are 3+2root2 and 3-2root 2

Answer 1

Answer:

x^2- 6x+1

Step-by-step explanation:

x^2-(sum)x + (product)

3+2root2+3-2root2=6

(3+2root2)(3-2root2)=3^2-(2root2)^2=9-8=1

Answer 2

Answer:

Step-by-step explanation: sum =3+2root2 and 3-2root 2

Sum =3+2root2 +3-2root2 =6

Product =(3+2root2) × (3 -2 root2)

=3^2-(2root 2)^2 = 9-8= 1

x^2 -(sum)x+product

x^2 -6x+1