Question

Write a quadratic polynomial whose zeroes are -3 and 4.​

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Answer:-

The Required Quadratic Polynomial is $\bf x^2-x-12.$

Explanation:-

Given:-

• Zeroes of a quadratic polynomial = -3 and 4.

To Find:-

• The Quadratic polynomial.

Concepts Used:-

If the zeores of a quadratic polynomial are $\bf\alpha\:\:And\:\:\beta$ then The form of the polynomial would be,

$\\ \orange{ \bigstar \boxed{ \pink{ \bf \bigg( {x}^{2} - ( \alpha + \beta )x + \alpha \beta . \bigg)}}}$

Now,

▪︎ Sum of zeroes = -3+4 = 1.

▪︎ Product of zeroes = -3×4 = -12.

Therefore,

Required Polynomial would be,

$\\ \tt\mapsto {x}^{2} - ( \alpha + \beta )x + \alpha \beta .$

$\\ \tt = {x}^{2} - (1)x + ( - 12).$

$\large \red{ \boxed{ \blue{ \bf = {x}^{2} - x - 12.}}}$

Therefore The Polynomial Is $\bf x^2-x-12.$