Question

write a quadratic polynomial , whose zeroes are -4 and 3

Answer 1

Answer:

THE ANSWERS IS

${x}^{2} + x - 12$

Step-by-step explanation:

THE FORMULA TO FIND QUADRATIC POLYNOMIAL IS

$k[ {x}^{2} - ( \alpha + \beta )x + ( \alpha \beta]$

THERE FORE,

$here \: \\ \alpha = - 4 \\ and \: \beta = 3 \\ \\ \: k[ {x}^{2} - ( - 4 + 3)x + ( - 4 \times 3)] \\ k( {x}^{2} - ( - 1)x - 12) \\ k( {x}^{2} + 1x - 12) \\ \\ when \: there \: is \: no \: denomintor \: in \: the \: given \: zeroes \: then \: k \: value \: is \: \\ 1 \\ there \: fore \: \\ {x}^{2} + x - 12$

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