Question

write a quadratic polynomial whose zeroes are 8 and -7​

Answer 1

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Given : Sum of zeroes = (∝ + β) = 8

Product of the zeroes = = 12

Required quadratic polynomial is x2 – (∝+β)x + ∝β  = x2 – (8)x + 12

Now, find the zeroes of the above polynomial

. Let f(x) = x2 – (8)x + 12 = x2 – 6x – 2x + 12 = (x -6)(x – 2) Substitute f

(x) = 0. either (x -6) = 0

or (x – 2) = 0  x = 6

or x = 2 2 and 6 are the zeroes of the polynomial.