Question

write a quadratic polynomial whose zeros are 2,-3​

Answer 1

Step-by-step explanation:

x^2-(2-3)x+(2(-3))

x^2-(-1)x+(-6)

x^2+1x-6

Answer 2

Step-by-step explanation:

Let roots of quadratic equation be a and b,then,

a=2,b=-3

Therefore required equation is:

x^2-(a+b)x+a*b=0

x^2-(2+(-3))x+(2)*(-3)=0

x^2-(2-3)x-6=0

x^2-1x-6=0

answer

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