Write a quadratic polynomial whose zeros are 3+root2 and 3-root 2
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Answered by
2
Answer:
x² - 6x + 7
Step-by-step explanation:
3+√2 is a zero => x-(3+√2) = x-3-√2 is a factor
3-√2 is a zero => x-(3-√2) = x-3+√2 is a factor
So a quadratic is
( x - 3 - √2 ) ( x - 3 + √2 )
= ( (x-3) - √2 ) ( (x-3) + √2 )
= (x-3)² - √2²
= x² - 6x + 9 - 2
= x² - 6x + 7
Answered by
1
Answer: x^2-6x+7
Please go through the the attachment...it's an alternate method..
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