write a quadratic polynomial whose zeros are -4/5 and 1/3
Answers
Answered by
44
sum of zeroes = -4/5 + 1/3
= (-12+5)/15
= -6/15
= -2/5
Product of zeroes = (-4/5)(1/3)
= -4/15
The quadratic polynomial is
= k [x² - (sum of zeroes)x + (product of zeroes)]
= k [x² - (-2/5)x + 4/15]
= k [x² + 2x/5 + 4/15]
Put k = 15 so as to make the polynomial not in fractions.
= 15x² + 6x + 4
hope it helps
= (-12+5)/15
= -6/15
= -2/5
Product of zeroes = (-4/5)(1/3)
= -4/15
The quadratic polynomial is
= k [x² - (sum of zeroes)x + (product of zeroes)]
= k [x² - (-2/5)x + 4/15]
= k [x² + 2x/5 + 4/15]
Put k = 15 so as to make the polynomial not in fractions.
= 15x² + 6x + 4
hope it helps
downtownpalaiovefr4:
thanku
Answered by
36
We know that quadratic polynomial = x²-(sum of zeroes)x+ product of zeroes =0
So sum of zeroes
= -4/5+1/3
= -12+5/15
=-7/15
Product of zeroes
=-4/5× 1/3
= -4/15
Quadratic polynomial with zeroes(-4/5,1/3 ) is x²- (-7/15)x+(-4/15)
=x²+7/15 x-4/15
=15x²+7x-4
Hope helped !
So sum of zeroes
= -4/5+1/3
= -12+5/15
=-7/15
Product of zeroes
=-4/5× 1/3
= -4/15
Quadratic polynomial with zeroes(-4/5,1/3 ) is x²- (-7/15)x+(-4/15)
=x²+7/15 x-4/15
=15x²+7x-4
Hope helped !
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