Write a quadratic polynomial whose zeros are 9 and 1/9 ?
Answers
Answered by
22
Hey
Here is your answer,
Zeroes=9,1/9
Sum of zeroes=9+1/9
=81+1/9
=82/9
Product of zeroes = 9x 1/9
=1
Quadratic polynomial = x^2 -(sum of zeroes)x + product of zeroes
=x^2 -82/9x+1
=9x^2 -82x +9
Hope it helps you!
Here is your answer,
Zeroes=9,1/9
Sum of zeroes=9+1/9
=81+1/9
=82/9
Product of zeroes = 9x 1/9
=1
Quadratic polynomial = x^2 -(sum of zeroes)x + product of zeroes
=x^2 -82/9x+1
=9x^2 -82x +9
Hope it helps you!
indreshpal1907p9jtgg:
thank u so much
Answered by
12
Heya !!!
Here is your answer.
Given Two zeroes are 9 and 1/9.
Sum of zeroes = 1/9 + 9 = 82/9
Product Of Zeroes = 1/9 × 9 = 1
Now, Using Quadratic Equation Formula....
p(x) = kx² - (sum of Zeroes)x + (product of zeroes)
p(x) = x² - (82/9)x + 1
Multiply Whole Equation by 9.....
p(x) = 9x² - 82x + 9
Hope You Got IT
Here is your answer.
Given Two zeroes are 9 and 1/9.
Sum of zeroes = 1/9 + 9 = 82/9
Product Of Zeroes = 1/9 × 9 = 1
Now, Using Quadratic Equation Formula....
p(x) = kx² - (sum of Zeroes)x + (product of zeroes)
p(x) = x² - (82/9)x + 1
Multiply Whole Equation by 9.....
p(x) = 9x² - 82x + 9
Hope You Got IT
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