Computer Science, asked by navyasuresh471, 1 month ago

write a query to display the details of students WHO born between 1-5-1987​

Answers

Answered by gksoftnick99
0

Answer:

Hope it will help uhh

Explanation:

-- Find all employees

SELECT *

FROM employee;

-- Find all clients

SELECT *

FROM clients;

-- Find all employees ordered by salary

SELECT *

from employee

ORDER BY salary ASC/DESC;

-- Find all employees ordered by sex then name

SELECT *

from employee

ORDER BY sex, name;

-- Find the first 5 employees in the table

SELECT *

from employee

LIMIT 5;

-- Find the first and last names of all employees

SELECT first_name, employee.last_name

FROM employee;

-- Find the forename and surnames names of all employees

SELECT first_name AS forename, employee.last_name AS surname

FROM employee;

-- Find out all the different genders

SELECT DISCINCT sex

FROM employee;

-- Find all male employees

SELECT *

FROM employee

WHERE sex = 'M';

-- Find all employees at branch 2

SELECT *

FROM employee

WHERE branch_id = 2;

-- Find all employee's id's and names who were born after 1969

SELECT emp_id, first_name, last_name

FROM employee

WHERE birth_day >= 1970-01-01;

-- Find all female employees at branch 2

SELECT *

FROM employee

WHERE branch_id = 2 AND sex = 'F';

-- Find all employees who are female & born after 1969 or who make over 80000

SELECT *

FROM employee

WHERE (birth_day >= '1970-01-01' AND sex = 'F') OR salary > 80000;

-- Find all employees born between 1970 and 1975

SELECT *

FROM employee

WHERE birth_day BETWEEN '1970-01-01' AND '1975-01-01';

-- Find all employees named Jim, Michael, Johnny or David

SELECT *

FROM employee

WHERE first_name IN ('Jim', 'Michael', 'Johnny', 'David');

Answered by kkvermasisai
0

Explanation:

-- Find all employees

SELECT *

FROM employee;

-- Find all clients

SELECT *

FROM clients;

-- Find all employees ordered by salary

SELECT *

from employee

ORDER BY salary ASC/DESC;

-- Find all employees ordered by sex then name

SELECT *

from employee

ORDER BY sex, name;

-- Find the first 5 employees in the table

SELECT *

from employee

LIMIT 5;

-- Find the first and last names of all employees

SELECT first_name, employee.last_name

FROM employee;

-- Find the forename and surnames names of all employees

SELECT first_name AS forename, employee.last_name AS surname

FROM employee;

-- Find out all the different genders

SELECT DISCINCT sex

FROM employee;

-- Find all male employees

SELECT *

FROM employee

WHERE sex = 'M';

-- Find all employees at branch 2

SELECT *

FROM employee

WHERE branch_id = 2;

-- Find all employee's id's and names who were born after 1969

SELECT emp_id, first_name, last_name

FROM employee

WHERE birth_day >= 1970-01-01;

-- Find all female employees at branch 2

SELECT *

FROM employee

WHERE branch_id = 2 AND sex = 'F';

-- Find all employees who are female & born after 1969 or who make over 80000

SELECT *

FROM employee

WHERE (birth_day >= '1970-01-01' AND sex = 'F') OR salary > 80000;

-- Find all employees born between 1970 and 1975

SELECT *

FROM employee

WHERE birth_day BETWEEN '1970-01-01' AND '1975-01-01';

-- Find all employees named Jim, Michael, Johnny or David

SELECT *

FROM employee

WHERE first_name IN ('Jim', 'Michael', 'Johnny', 'David');

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