Physics, asked by nahurafatima, 1 month ago

write a relation to get no of orbitals by using subshell 1​

Answers

Answered by aryankamat11
0

Answer:

Subject matter in this questions

Answered by nuhamu7
1

Answer:

That depends on the subshell.

Explanation:

Electrons that surround an atom's nucleus are distributed on specific energy levels, or shells.

Each shell is made up of a different number of subshells. More specifically, the number of subshells a shell can have increases as you move away from the nucleus.

You can use quantum numbers to illustrate this point.

The principal quantum number,  n , gives you the energy level, or shell.

Now, the number of subshells is given by the angular momentum quantum number,  

l , which can take values from  0 to  n − 1 .

This means that you will have

1.  n  =  1 ⇒ l  =  0  →  the first shell only has one subshell, s

2. n = 2 ⇒ l  =  0 ,  1  → the second shell has two subshells: s and p

3. n =  3 ⇒  1  =  0 ,  1 ,  2  → the third shell has three subshells, sp, p, and d

                                         ⋮

and so on.

The number of orbitals each subshell contains is given by the magnetic quantum number,  ml, which takes values from   − l  to l .

So, for example, how many orbitals would you say the 2p-subshell has?

Well, the 2p-subshell has l   = 1, which means that   ml can be

ml  =  { −1 , 0,  1 } →  the 2p-subshell contains 3 orbitals.

How about the 3d-subshell?

For the 3d-subshell, you know that  

l= 2 . This means that  m l  can be

m l = { −2 ,  − 1 ,  0 ,  1 ,  2  }  → the 3d-subshell contains 5 orbitals.

So, as a conclusion, you get th number of orbitals per subshell from the principal quantum number,  n , which in turn gives you the value of the angular momentum quantum number,  l .

The magnetic quantum number, the ones that tells you exactly how many orbitals you get per subshell, will always take values from  − l  to l , so if you know l , you automatically know ml .

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AAHHHHHhhhhh! I'm so tired now, need a break now =_= and I'm really so so sorry for answering you late but what can I do, it just took a lot of time for me to explain and answer this question  :|

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