Math, asked by Bhavna26, 1 year ago

write a Roman numeral of 4311​


Anonymous: MCCCII is ur ans
Anonymous: sorry its wrong

Answers

Answered by Anonymous
1

HeRe Is Your Ans ⤵

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➡4310 = IVCCCX

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Answered by ishitaaparajita73
1

4,311 =

4,000 + 300 + 10 + 1 =

M(V) + CCC + X + I =

M(V)CCCXI;

M(V)CCCXI is a group of numerals in additive and subtractive notation.

Subtractive notation = a group of two numerals, one of a lower value preceding another larger one, the only allowed ones are: IV, IX, XL, XC, CD, CM, M(V), M(X), (X)(L), (X)(C), (C)(D), (C)(M) - to calculate the value subtract the first symbol from the second. Subtractive notation of the Roman numerals

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