Write a second degree polynomial p(x) with p(0)=0 p(1) =2. P(2)=5
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x^2+3x is answer
as let the polynomial be ax^2+bx+c
now putting zero we got C = 0
and by putting 1 and equating by 2 we have equation a+b= 2
now by putting 2 we have 4a+2b=5 by solving equation we have a = 1/2 and b = 3/2 hence we have the polynomial
as let the polynomial be ax^2+bx+c
now putting zero we got C = 0
and by putting 1 and equating by 2 we have equation a+b= 2
now by putting 2 we have 4a+2b=5 by solving equation we have a = 1/2 and b = 3/2 hence we have the polynomial
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