Computer Science, asked by pranayeesaha0009, 9 months ago

write a series program in Java : S= x!/1+(x+2)!/(1+2)+(x+4)!/(1+2+3)+....(10 terms)

Answers

Answered by divyanshtiwarivk
0

Answer:

1+203+400 +2+3Is DD I have

Answered by kriyanshumeena67
3

Answer:

Java program to get the sum of the series

import java.io.*;

class MathSeries {

// Function to get the series

static double Series(double x, int n)

{

double sum = 1, term = 1, fct, j, y = 2, m;

// Sum of n-1 terms starting from 2nd term

int i;

for (i = 1; i < n; i++) {

fct = 1;

for (j = 1; j <= y; j++) {

fct = fct * j;

}

term = term * (-1);

m = Math.pow(x, y) / fct;

m = m * term;

sum = sum + m;

y += 2;

}

return sum;

}

// Driver Code

public static void main(String[] args)

{

double x = 3;

int n = 4;

System.out.println(Math.round(Series(x, n)

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THE ANSWER ABOVE IS WRONG

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