Question

write a sketal equal for the following equation :- hydrogen sulphide reacts with sulphur dioxide to form sulphur and water

Answer 1

Hello! Let me try to answer this :)

$2H_{2}S + SO_{2} =\ \textgreater \ 3S + 2H_{2}O$

Thank you, please correct if there are any mistakes ^ ^

Answer 2

Answer:

Let, the volume of O

3

=x mL.

Volume of O

2

present =(600−x) mL

22400 mL of O

3

and O

2

at STP will weight 48 g and 32 g respectively.

The weight of x mL of O

3

=

22400

x×48

g.

The weight of (600−x) mL of O

2

=

22400

(600−x)

×32.

Total weight of ozonised O

2

(600mL) =

22400

48x

+

22400

(600−x)×32

=1.0.

∴x=200 mL