Question

write a suitable identity and expand (4a-2b-3c)²​

Answer 1

Answer:

(4a-2b-3c) (4a-2b-3c)

Answer 2

Answer:

(4a-2b-3c)²

= [(4a)+(-2b)+(-3c)]²

$using \: (x {}^{2}+y {}^{2} + z {}^{2} + 2xy + 2yz + 2zx)$

= (4a)²+ (-2b)²+ (-3c)²+ 2(4a)(2b) + 2(-2b)(-3c) + 2(-3c)(4a)

= 16a²+ 4b²+ 9c²+ 16ab+ 12bc- 24ca

=16a²+ 4b²+ 9c²+ 16ab+ 12bc- 24ac