Question

write a two digit number with sum of its digits 9 . dum of the digit of a two digit number is 9 . the number got by inter changing the digit is 27 more than the original number. what is the number ?​

Answer 1

Answer:

36 is the number

Step-by-step explanation:

let the number be (10x+y)

such that x + y = 9 -(1)

and, (10y+x ) = (10x+y) + 2

(10y-y) - (10x -x) = 27

9y - 9x = 27

9(y-x) = 27

y - x = 27/9 = 3

y = 3 + x

y = 3 + (9-y)

y + y =3 + 9

2y = 12

y = 12/2

y = 6

putting y = 6 in (1), we get

x + 6 = 9

x = 9 - 6

x = 3

therefore, required number is

10(3) + 6 = 30 + 6 = 36