Question

write about image formation in concave mirror with diagram .

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Answer 1

Answer:

Concave mirrors form both real and virtual images. When the concave mirror is placed very close to the object, a virtual and magnified image is obtained and if we increase the distance between the object and the mirror, the size of the image reduces and real images are formed.

Answer 2

Image formation in Concave mirror:

$\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{cccc}\sf \pink{Position_{\:(object)}} &\sf \purple{Position_{\:(image)}} &\sf \red{Size_{\:(image)}} &\sf \blue{Nature_{\:(image)}}\\\frac{\qquad \qquad \qquad \qquad}{}&\frac{\qquad \qquad \qquad \qquad}{}&\frac{\qquad \qquad \qquad \qquad\qquad}{}&\frac{\qquad \qquad \qquad \qquad\qquad}{}\\\sf At \:Infinity &\sf At\: F&\sf Highly\:Diminished&\sf Real\:and\:Inverted\\\\\sf Beyond\:C &\sf Between\:F\:and\:C&\sf Diminished&\sf Real\:and\:Inverted\\\\\sf At\:C &\sf At\:C&\sf Same\:Size&\sf Real\:and\:Inverted\\\\\sf Between\:C\:and\:F&\sf Beyond\:C&\sf Enlarged&\sf Real\:and\;Inverted\\\\\sf At\:F&\sf At\:Infinity&\sf Highly\: Enlarged&\sf Real\:and\:Inverted\\\\\sf Between\:F\:and\:P&\sf Behind\:the\:mirror&\sf Enlarged&\sf Erect\:and\:Virtual\end{array}}\end{gathered}\end{gathered}\end{gathered}$

Diagram:

• Kindly refer to the attachment for the diagram.

Additional information:

Ray diagram convex mirror:

$\setlength{\unitlength}{0.7 cm}\begin{picture}(0,0)\thicklines\put(0,0){\line(1,0){12}}\qbezier(10.49,0)(10.5,1.8)(8.5,3.8)\qbezier(10.49,0)(10.5,-1.8)(8.5,-3.8)\put(7,0){\circle*{0.2}}\put(4,0){\circle*{0.2}}\put(2,0){\vector(0,1){1.5}}\linethickness{0.1mm}\put(2,1.5){\line(1,0){8.2}}\qbezier(10.2,1.5)(7,0)(3.8,-1.5)\put(2,1.5){\line(4,-3){6.77}}\thicklines\put(5.17,0){\vector(0,-1){0.85}}\put(6,1.496){\vector(1,0){0}}\put(6.3,1.496){\vector(1,0){0}}\put(4.2,-1.33){\vector(-3,-2){0}}\put(8,-2.96){\vector(3,-2){0}}\put(7.5,-2.64){\vector(-3,2){0}}\put(1.9,-0.5){\sf B}\put(1.9,1.7){\sf A}\put(3.7,-0.5){\sf C}\put(7.2,-0.5){\sf F}\put(5,-1.4){\sf A'}\put(5,0.2){\sf B'}\put(10.7,0.2){\sf P}\put(10.35,1.45){\sf D}\put(9,-4){\sf E}\end{picture}$