Write about the Stability of cyclopropane.
Answers
The triangular structure of cyclopropane requires the bond angles between carbon-carbon covalent bonds to be 60°. This is far less than the thermodynamically most stable angle of 109.5° (for bonds between atoms with sp3 hybridised orbitals) and leads to significant ring strain.
Chemical formula: C3H6
Magnetic susceptibility (χ): -39.9·10−6 cm3/mol
Boiling point: −33 °C (−27 °F; 240 K)
Melting point: −128 °C (−198 °F; 145 K) the cylclopropane is unstable in nature.The reason for ring strain can be seen through the tetrahedral carbon model. ... This bond angle causes cyclopropane and cyclobutane to have a high ring strain. However, molecules, such as cyclohexane and cyclopentane, would have a much lower ring strain because the bond angle between the carbons is much closer to 109.5 degree
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