Question

write al the quantum number of last electrons of atomic number 12.​

Answer 1

Answer:

n=3, l=0, m=0.

3s is the orbital number.

Answer 2

Explanation:

$principal\: quantum \:number(n)=3$

$Spin\: quantum\: no.(m_{s})= \frac{-1}{2}$

$Azimulthal \:quantum\: no.(l)=0$

$Magnetic \:quantum\: no.(m_{l})=0$