write alfa = 5 on one side of a card sheet and alfa =-6 on one side of apotger card sheet B= 3 on its back side .from there values . from differents values of (alfa +B) and (alfaB ) .using the valurs .from quadratic equation by math practical
Answers
Step-by-step explanation:
Given:−
Current, I = 20 mA
Time taken, t = 50 seconds
Charge of an electron, e = 1.6 × 10^-19
\underline{\underline{\bf{\green{To\:Find\::-}}}}
ToFind:−
Number of electrons = ?
\underline{\underline{\bf{\green{Solution\::-}}}}
Solution:−
★ Converting unit of current into A :-
✏ㅤㅤㅤ1 mA = 0.001 A
✏ㅤㅤㅤ20 mA = 20 × 0.001
✏ㅤㅤㅤ20 mA = 0.02 A
★ Using formula :-
\qquad\red\bigstar\:{\underline{\boxed{\bf{I = \dfrac{Q}{t}}}}}★
I=
t
Q
\qquad\leadsto\quad\sf I = \dfrac{ne}{t}⇝I=
t
ne
\qquad\leadsto\quad\sf 0.02 = \dfrac{n\:\times\:1.6\:\times\:10^{-19}}{50}⇝0.02=
50
n×1.6×10
−19
\qquad\leadsto\quad\sf 0.02 \:\times\:50 = (1.6\:\times\:10^{-19})n⇝0.02×50=(1.6×10
−19
)n
\qquad\leadsto\quad\sf \dfrac{1}{1.6\:\times\:10^{-19}} = n⇝
1.6×10
−19
1
=n
\qquad\leadsto\quad\sf 0.625\:\times\:10^{19} = n⇝0.625×10
19
=n
\qquad\leadsto\quad\bf{ n = \red{6.25\:\times\:10^{18}}}⇝n=6.25×10
18
\small\therefore\:{\underline{\sf{Hence,\:number\:of\:electrons\:=\:\bf{6.25\:\times\:10^{18}}}}}∴
Hence,numberofelectrons=6.25×10
Step-by-step explanation:
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