Math, asked by pawandhudhe4772007, 1 month ago

write alfa = 5 on one side of a card sheet and alfa =-6 on one side of apotger card sheet B= 3 on its back side .from there values . from differents values of (alfa +B) and (alfaB ) .using the valurs .from quadratic equation by math practical

Answers

Answered by VexoXDwayne
0

Step-by-step explanation:

Given:−

Current, I = 20 mA

Time taken, t = 50 seconds

Charge of an electron, e = 1.6 × 10^-19

\underline{\underline{\bf{\green{To\:Find\::-}}}}

ToFind:−

Number of electrons = ?

\underline{\underline{\bf{\green{Solution\::-}}}}

Solution:−

★ Converting unit of current into A :-

✏ㅤㅤㅤ1 mA = 0.001 A

✏ㅤㅤㅤ20 mA = 20 × 0.001

✏ㅤㅤㅤ20 mA = 0.02 A

★ Using formula :-

\qquad\red\bigstar\:{\underline{\boxed{\bf{I = \dfrac{Q}{t}}}}}★

I=

t

Q

\qquad\leadsto\quad\sf I = \dfrac{ne}{t}⇝I=

t

ne

\qquad\leadsto\quad\sf 0.02 = \dfrac{n\:\times\:1.6\:\times\:10^{-19}}{50}⇝0.02=

50

n×1.6×10

−19

\qquad\leadsto\quad\sf 0.02 \:\times\:50 = (1.6\:\times\:10^{-19})n⇝0.02×50=(1.6×10

−19

)n

\qquad\leadsto\quad\sf \dfrac{1}{1.6\:\times\:10^{-19}} = n⇝

1.6×10

−19

1

=n

\qquad\leadsto\quad\sf 0.625\:\times\:10^{19} = n⇝0.625×10

19

=n

\qquad\leadsto\quad\bf{ n = \red{6.25\:\times\:10^{18}}}⇝n=6.25×10

18

\small\therefore\:{\underline{\sf{Hence,\:number\:of\:electrons\:=\:\bf{6.25\:\times\:10^{18}}}}}∴

Hence,numberofelectrons=6.25×10

Answered by krishna989891
0

Step-by-step explanation:

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