Question

write all 3-digit number using 2 3 4 taking each digit only once​

Answer 1

Answer:

The 3-digit numbers formed by 2, 3 and 4 by taking each digit only once are 234, 324, 243, 342, 423 and 432.

Answer 2

$\huge\sf\color{orange}\underline{Given}:-$

write all 3-digit number using 2 3 4 taking each digit only once

.

$\huge\sf\color{orange}\underline{Solution}:-$

Given number → 2 3 4

.

.

So, first 3-digit number is

$\fbox\red{234}$

.

second 3-digit number is

$\fbox\red{243}$

.

third 3-digit number is

$\fbox\red{324}$

.

fourth 3-digit number is

$\fbox\red{342}$

.

fifth 3-digit number is

$\fbox\red{423}$

.

And sixth 3-digit number is

$\fbox\red{432}$

$\tt\orange {\therefore~ the ~all~ 3-digit ~number~made~by~ using ~2 ~3~ 4 ~are~}$

$\tt\red{→234,~243,~ 324,~342,~423~and~432.}$