Question

write all four quantum numbers for electron occupying 3p6​

Answer 1

Answer:

n=3

l=1

m=+1,0,-1

ms=+1/2 or-1/2

Explanation:

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Answer 2

Answer:

In an atom, electrons are characterized by four quantum numbers, which are used to determine the electron's energy, position, and other properties.

The four quantum numbers are:

1. Principal quantum number (n)
2. Azimuthal quantum number (l)
3. Magnetic quantum number (m)
4. Spin quantum number (s)

Explanation:

In the case of an electron occupying the 3p6 orbital, the four quantum numbers are as follows:

Principal quantum number (n) = 3

The principal quantum number represents the energy level of the electron. For the 3p6 electron, it is in the third energy level.

Azimuthal quantum number (l) = 1

The azimuthal quantum number represents the sublevel of the electron. For the 3p6 electron, the sublevel is p, and l = 1.

Magnetic quantum number (m) = 0

The magnetic quantum number represents the orientation of the electron's orbital in space. For the 3p6 electron, there are three p orbitals (m = -1, 0, 1), and the electron is in the 0 orbital.

Spin quantum number (s) = -1/2

The spin quantum number represents the electron's spin. Electrons can have a spin of +1/2 or -1/2. For the 3p6 electron, the spin is -1/2.

Therefore, the four quantum numbers for an electron occupying the 3p6 orbital are n=3, l=1, m=0, and s=-1/2

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