Write all four quantum numbers of last electron of fe
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And so we would write the following electronic configuration with respect to the atom....
1
s
2
2
s
2
2
p
6
3
s
2
3
p
6
4
s
2
3
d
6
But upon oxidation.......we gets
F
e
3
+
, and the standard electronic configuration is.....
{
1
s
2
2
s
2
2
p
6
3
s
2
3
p
6
3
d
5
}
3
+
So the last electron is from one of the (degenerate!)
d-orbitals....
And thus...........
n
=
3
;
l
=
2
(i.e. we have d-orbitals with 2 nodal planes)
;
m
l
=
−
2
,
−
1
,
0
,
1
,
or
2
;
m
s
=
±
1
2
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