write all other trigonometric ratios of angle A in terms of sec A
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Answered by
6
Answer:
secA=cosA1⇒cosA=secA1
sin2A+cos2A=1⇒sin2A=1−sec2A1⇒sinA±1−sec2A1
tanA=sec2A−1
cotA=tanA1=sec2A−11
cscA=sinA1=±sec2A−1sec2A
Answered by
2
secA=
cosA
1
⇒cosA=
secA
1
sin
2
A+cos
2
A=1⇒sin
2
A=1−
sec
2
A
1
⇒sinA±
1−
sec
2
A
1
tanA=
sec
2
A−1
cotA=
tanA
1
=
sec
2
A−1
1
cscA=
sinA
1
=±
sec
2
A−1
sec
2
A
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