Write all possible structural isomers of alcohol having molecular formula C6H12O .Give their IUPAC names .Classify them as primary ,secondary, tertiary alcohols .Identify optically active alcohols amongst them
Answers
Answer:
Making use of symmetry, and the fact that it must be a ketone, the carbonyl group can only move between carbons 2 and 3. That makes for the first two isomers.
Two more isomers involve shifting the terminal methyl group up one to carbon 4.
The fifth and sixth isomers are enantiomers, the top of which is R and the bottom of which is S. The idea was to move the methyl group up one more to carbon 3, making a sec-butyl group off of acetone.
The seventh isomer was simply to make a tert-butyl group hanging off of acetone.
We know that a carbonyl group can only exist at spots that give an
s
p
2
hybridization, so there is no structure for the carbonyl on carbon 3 when carbon 3 has a tert-butyl group. Similarly, there is no structure for which the carbonyl is on carbon 3 while the sec-butyl is also on carbon 3.
Answer:
In the IUPAC system, alcohols are named by changing the ending of the parent alkane name to -ol. Alcohols are classified according to the number of carbon atoms attached to the carbon atom that is attached to the OH group