Question

Write all subsets of { sin A sin B Sin C}​

Answer 1

Answer:

let the number of elements in A be m and B be n

therefore the total number of subsets of A is 2

m

and number of subsets of B is 2

n

given 2

m

−2

n

=960

we know from this equation that m>n

therefore taking n common we get

2

n

(2

m−n

−1)=960

as 2

(

m−n)−1 is odd the even part is only 2

n

960 can be written as 2

6

×15

therefore from above equation we can observe that n=5

and $$2^(m-5)-1$=15$

⇒2

(

m−5)=16 so m=9

therefore n(A)-n(B)=m-n=4

Answer 2

HEY MATE HERE'S YOUR

Answer:

{(null set),(sina),(sinb),(sinc),(sina,sinb),(sinb,sinc),(sina,sinc),(sina,sinb,sinc}

Step-by-step explanation:

where are (,)

MMM

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