Write all the 2 digit number which when added to 27 gets reversed.
By some easy method
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Let the number is such that it has x in tens place and y in ones place.
So the number is = (10x + y)
So 27+(10x+y)=10y+x [Reversed]
So 9x + 27 = 9y => x+3=y
So x can't be 0 as it is two digit number so if :
- x=1,y=4
- x=2,y=5
- x=3,y=6
- x=4,y=7
- x=5,y=8
- x=6,y=9
- x=7,y=10 (not possible as y is a single digit number)
So the numbers are : 14,25,36,47,58,69.
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