Physics, asked by Anonymous, 1 year ago

Write all The Formulas of derivatives .....for class +1 ....................Please Fast ...............

Answers

Answered by kvnmurty
6
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   function             derivative
=============================
   constant                    0
       x                          1
     x^n                        n x^{n-1}
   f ( g(x) )                  f ' ( g(x) )  *  g' (x)
   Sin x                       cos x
   Cos x                      - sin x
   Tan x                      sec^2  x
   Sec x                       sec x   tan x
   1/x                          - 1/ x^2
   Ln x                       1/x
   e^x                         e^x
   f (x) + g(x)              f ' (x)  + g ' (x)
   f (x)  * g (x)               f (x)  * g ' (x)  + f '(x) * g(x)
     f (x) / g(x)              [ f '(x) g(x) - f(x) g'(x) ] / [ g(x) ]^2
 
   Sinh (x)                    Cosh (x)
   Cosh (x)                   sinh (x)
   Tanh (x)                    Sech^2 (x)

   a^x                           a^x * ln a
   a * f(x)                      a * f ' (x)
   a * f^n (x)                  a * n * f^{n-1} (x) * f '(x)

   Sin⁻¹ x                        1/√(1-x²)
   Cos⁻¹ x                    - 1/√(1-x²)
  
   tan⁻¹ x                      1 / (1+x²)

   There are other trigonometric, inverse trigonometric, hyperbolic and inverse hyper bolic functions...  also..


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Anonymous: YEs sure
Answered by darshmenon05
0

Answer:

Explanation:

Power Rule: (d/dx) (xn ) = nxn-1

Derivative of a constant, a:  (d/dx) (a) = 0

Derivative of a constant multiplied with function f: (d/dx) (a. f) = af’

Sum Rule: (d/dx) (f ± g) = f’ ± g’

Product Rule: (d/dx) (fg)= fg’ + gf’  

Quotient Rule:ddx(fg) = gf′–fg′g2

ddx(sin x)=cos x

ddx(cos x)=–sin x

ddx(tan x)=sec2x

ddx(cot x=−cosec2x

ddx(sec x)=sec x tan x

ddx(cosec x)=−cosec x cot x

ddx(sinh x)=cosh x

ddx(cosh x)=sinh x

ddx(tanh x)=sech2x

ddx(coth x)=−cosech2x

ddx(sech x)=−sech x tanh x

ddx(cosech x)=−cosech x coth x

se trigonometric functions.

ddx(ax)=axlna

ddx(ex)=ex

ddx(loga x) = 1(ln a)x

ddx(ln x)=1/x

Chain Rule: dydx = dydu×dudx = dydv×dvdu×dudx

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