Question

write all the integers that like remainder 1 when its divided by 3​

Answer 1

❤◀✨ANSWER IS✨▶❤

Clearly, the two digits numbers which leave remainder 1 when divided by 3 are 10,13,16,...,97.

This is an AP with first term a=10,

common difference d=3 and last term l=97.

Let there be n terms in this AP, then

an=97=a+(n−1)d

=97=a+(n−1)d∴10+(n−1)×3=977

10+3n−3=97

10+3n−3=973n=97+3−10

10+3n−3=973n=97+3−103n=90

10+3n−3=973n=97+3−103n=90∴n=30

10+3n−3=973n=97+3−103n=90∴n=30∴ Required sum=2n[a+l]=2/30[10+97]=15×107=1605

Answer 2

Answer:

4 7 10 13 16 19 ids this right