Write all the numbers that can be formed from 628 10 lines
Answers
Step-by-step explanation:
Five years hence Father's age will be three times his Daughter, five years ago Father was seven times as old as his Daughter. Find their Present Ages.
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\large \clubs \: \bf Given : -♣ Given: −
Five years hence Father's age will be three times his Daughter.
Five years ago Father was seven times as old as his Daughter.
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\large \clubs \: \bf To \: Find : -♣ ToFind: −
Their Present Ages.
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\large \clubs \: \bf Solution : -♣ Solution: −
Let,
Present Age of Father = x years
Present Age of Daughter = y years
《 5 Years Hence 》
Age of Father = (x + 5) years
Age of Daughter = (y + 5) years
✏ According To Question :
\begin{gathered} \red{\text{x + 5 = 3(y + 5)}} \\ \end{gathered}x + 5 = 3(y + 5)
\begin{gathered}:\longmapsto\text{x + 5 = 3y + 15} \\ \end{gathered}:⟼x + 5 = 3y + 15
\begin{gathered}:\longmapsto\text x = 15 - 5 +3\text y\\ \end{gathered}:⟼x=15−5+3y
:\longmapsto \bf x =3\text y+10\: - - - (1):⟼x=3y+10−−−(1)
《 5 Years Ago 》
Age of Father = (x - 5) years
Age of Daughter = (y - 5) years
✏ According To Question :
\begin{gathered} \red{ \text{x} - 5 = 7(\text y - 5)} \\ \end{gathered}x−5=7(y−5)
\begin{gathered}:\longmapsto\text x - 5= 7\text y - 35 \\ \end{gathered}:⟼x−5=7y−35
\begin{gathered}:\longmapsto\text x - 7\text y = - 35 + 5 \\ \end{gathered}:⟼x−7y=−35+5
\bf:\longmapsto x - 7y = - 30 \: - - - (2):⟼x−7y=−30−−−(2)
✏ Putting (1) in (2) :
\begin{gathered}3\text y + 10 - 7\text y = - 30 \\ \end{gathered}3y+10−7y=−30
\begin{gathered}:\longmapsto \cancel- 4\text y = \cancel- 40 \\ \end{gathered}:⟼−4y=−40
\begin{gathered}:\longmapsto\text y = \cancel\dfrac{40}{4} \\ \end{gathered}:⟼y=440
\purple{ \Large :\longmapsto \underline {\boxed{{\bf y = 10} }}}:⟼ y=10
Putting Value of y in (1) :
\begin{gathered}:\longmapsto\text x = 3 \times 10 + 10 \\ \end{gathered}:⟼x=3×10+10
\begin{gathered}:\longmapsto\text x = 30 + 10 \\ \end{gathered}:⟼x=30+10
\purple{ \Large :\longmapsto \underline {\boxed{{\bf x = 40} }}}:⟼ x=40
Hence,