write all the numbers that you can make using the digits 3,1 and 8 once only. helppp
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Answered by
5
Answer:
318
813
138
381
831
183
........ . ..
Answered by
2
Digits given = 3
i.e. 3 , 1 , 8
as it is given in the question that one digit can only be used once ,
therefore
We can use Permutation here or fundamental principle of counting
As it will form a three digit number , then
In Hundred's place we can use any one of the 3 digits
In Ten's place we can use any one of the 2 digits
and In Unit's place we can only use 1 digit
Hence , Total numbers formed = 3 × 2 × 1
= 6
Also , the numbers are
138 , 183 , 318 , 381 , 813 , 831.
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I hope you understand
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