Question

Write all the other trignometric ratios of angleA in terms of secA.
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Answer 1

Answer:

tanA= √(sec^2A-1)

cosA= 1/(secA)

cotA= 1/√(sec^2A-1)

sinA= √(sec^2A-1)/secA

cosecA= secA/√(sec^2A-1)

Step-by-step explanation:

• tan^2A + 1= sec^2 A (identity)

tanA = √(sec^2A-1)

• cosA is the reciprocal of sec A
• cotA is the reciprocal of tanA
• tanA = sinA / cosA

which means that sinA = tanAcosA

sinA= √(sec^2-1)/secA

• cosecA is the reciprocal of sinA