Write all the other trigonometric ratios of ∠A in terms of sec A.
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Answer:
We know,
cosA=secA1
We know,
sin2A+cos2A=1
sin2A=1−cos2A
sinA=1−(secA1)2=sec2Asec2A−1=secAsec2A−1
∴sinA=secAsec2A−1
We know,
cosec A=sinA1
∴cosec A=sec2A−1secA
We know,
cotA=sinAcosA==secA
Step-by-step explanation:
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