Question

Write all the possible values of x for which 6×86 is divisible by 2 and 3 both.
with process​​​

Answer 1

Step-by-step explanation:

as units place 6 is even no., the no is divisible by 2 for any value of x

for a no. to be divisible by 3, sum of digits is divisible by 3

6+x+8+6 = 20+x

20+x = 18 +2+x

18 is divisible by 3

for 2+x to be divisible by 3

I.e 2+x = 3y

x,y are natural no.s and x is a single digit no

when y=1

2+x = 3

x= 3-2 = 1

when y=2

2+x =3×2=6

x= 6-2 = 4

when y= 3

2+x = 3×3 =9

x = 9-2 = 7

when y = 4

2+x = 3×4=12

x = 12-2 = 10

it's a 2digit no.

so, for values of x=1, 4, 7 the no. 6x86 is divisible by both 2 and 3

Answer 2

Step-by-step explanation:

$1 \: \: 4 \: \: and \: 7$

$because \: if \: the \: sum \: of \: all \: digits \:$

$equals \: to \: 3 \: \: 6 \: and \: 9$

$it \: is \: divisible \: by \: 3$

$and \: if \: x \: is \: equal \: to \: 1 \: \: 4 \: and \: 7$

$it \: would \: be \: equal \: to \: 3 \: \: 6 \: and \: 9$