Question

Write all the possible values of x for which 6x86 is divisible by 2 and 3 both.
with process​

Answer 1

Answer:

We know that the given number

67y19

is divisible by 9.

And, if a number is divisible by 9 then sum of digits must be a multiple of 9.

i.e., 6+7+y+1+9= multiple of 9

y+23=0,9,18,27…

Here y is a digit, where, y can have values between 0 and 9.

y+23=27 which gives y=4.

Hence, y=4.

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Answer 2

1,4,7

because if the sum of all digits equals to 3 ,6 and 9

it is divisible by 3

and if x is equal to 1,4 and 7

it would be equal to 3 6 or 9