Question

Write all the trigonometric identities .☠☠No spams ❎
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Answer 1

Terms in this set (8)

Terms in this set (8)Reciprocal: csc(θ) = csc(θ) = 1/sin(θ)

Terms in this set (8)Reciprocal: csc(θ) = csc(θ) = 1/sin(θ)Reciprocal: sec(θ) = sec(θ) = 1/cos(θ)

Terms in this set (8)Reciprocal: csc(θ) = csc(θ) = 1/sin(θ)Reciprocal: sec(θ) = sec(θ) = 1/cos(θ)Reciprocal: cot(θ) = cot(θ) = 1/tan(θ)

Terms in this set (8)Reciprocal: csc(θ) = csc(θ) = 1/sin(θ)Reciprocal: sec(θ) = sec(θ) = 1/cos(θ)Reciprocal: cot(θ) = cot(θ) = 1/tan(θ)Ratio: tan(θ) = tan(θ) = sin(θ)/cos(θ)

Terms in this set (8)Reciprocal: csc(θ) = csc(θ) = 1/sin(θ)Reciprocal: sec(θ) = sec(θ) = 1/cos(θ)Reciprocal: cot(θ) = cot(θ) = 1/tan(θ)Ratio: tan(θ) = tan(θ) = sin(θ)/cos(θ)Ratio: cot(θ) = cot(θ) = cos(θ)/sin(θ)

Terms in this set (8)Reciprocal: csc(θ) = csc(θ) = 1/sin(θ)Reciprocal: sec(θ) = sec(θ) = 1/cos(θ)Reciprocal: cot(θ) = cot(θ) = 1/tan(θ)Ratio: tan(θ) = tan(θ) = sin(θ)/cos(θ)Ratio: cot(θ) = cot(θ) = cos(θ)/sin(θ)Pythagorean: sin costs = $1. ...

Terms in this set (8)Reciprocal: csc(θ) = csc(θ) = 1/sin(θ)Reciprocal: sec(θ) = sec(θ) = 1/cos(θ)Reciprocal: cot(θ) = cot(θ) = 1/tan(θ)Ratio: tan(θ) = tan(θ) = sin(θ)/cos(θ)Ratio: cot(θ) = cot(θ) = cos(θ)/sin(θ)Pythagorean: sin costs = $1. ... Pythagorean: I tan = get sic. ...

Terms in this set (8)Reciprocal: csc(θ) = csc(θ) = 1/sin(θ)Reciprocal: sec(θ) = sec(θ) = 1/cos(θ)Reciprocal: cot(θ) = cot(θ) = 1/tan(θ)Ratio: tan(θ) = tan(θ) = sin(θ)/cos(θ)Ratio: cot(θ) = cot(θ) = cos(θ)/sin(θ)Pythagorean: sin costs = $1. ... Pythagorean: I tan = get sic. ... Pythagorean: I cut = crescent rolls.

Answer 2

Trigonometric Identies:

${\sin}^2\:\theta+{\cos}^2\:\theta\:=\:1\\\\1+{\tan}^2\:\theta\:=\:{\sec}^2\:\theta\\\\1+{\cot}^2\:\theta\:=\:{\csc}^2\:\theta$

Trigonometric Ratios

$\sin\:\theta\:=\:\dfrac{Perpendicular}{Hypotenuse} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\\\\cos\:\theta\:=\:\dfrac{Base}{Hypotenuse} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\\\\tan\:\theta\:=\:\dfrac{\sin\:\theta}{\cos\:\theta}\:=\:\dfrac{Perpendicular}{Base} \: \: \: \: \\\\\sec\:\theta\:=\:\dfrac{1}{\cos\:\theta}\:=\:\dfrac{Hypotenuse}{Base} \: \: \: \: \: \: \: \: \: \: \: \\\\\cosec\:\theta\:=\:\dfrac{1}{\sin\:\theta}\:=\:\dfrac{Hypotenuse}{Perpendicular}\\\\\cot\:\theta\:=\:\dfrac{1}{\tan\:\theta}\:=\:\dfrac{Perpendicular}{Hypotenuse} \: \: \: \:$

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