Question

write all the trigonometric ratio of angle A in terms of cot A​

Answer 1

Answer:

Sin A =1/cosec A.

TanA=sinA / cosA. = 1/cosecA /cos A

Cos=(90-A)=sinA= 1/cosecA

SecA=cosec(90-A)

CotA=cosA/sinA=cosA/1/SinA

Answer 2

$\sec(a) = \frac{h}{b} = \frac{ac}{ab} = \frac{x}{ab} \\ ab = \frac{x}{ \sec( a ) } \\ {h}^{2} = {p}^{2} + {b}^{2} \\ {x}^{2} = {p}^{2} + ({ \frac{x}{2 \sec(a) } })^{2} \\ {x}^{2} = {p}^{2} + \frac{ {x}^{2} }{ { \sec(a) }^{2} } \\ {x}^{2} - \frac{ {x}^{2} }{ { \sec(a) }^{2} } = {p}^{2} \\ {p}^{2} = \frac{ {x}^{2}( { \sec(a) }^{2} ) - {x}^{2} }{ { \sec(a) }^{2} } \\ {p}^{2} = 0\\p=0$

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