Math, asked by CaptainBrainly, 11 months ago

Write all the Trigonometric ratios, identities.

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Answers

Answered by theironman
13

Answer:

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Step-by-step explanation:

sin^2 +cos^2 = 1 first identity. sec^2 - tan^2 =1 second identity. cosec^2- cot ^2=1 third identity. tan= sin/ cos and cot =cos/ sin

Answered by Anonymous
72

Solution :

Step-by-step explanation:

Trigonometry :

Trigonometry is a branch of mathematics which deal with the study of three sides measurement.

There are six trigonometric ratios :

\large \text{$\sin \theta=\dfrac{perpendicular}{hypotenuse} $}\\\\\\\large \text{$\cos \theta=\dfrac{base}{hypotenuse} $}\\\\\\\large \text{$\tan \theta=\dfrac{perpendicular}{base} $}\\\\\\\large \text{$\cot \theta=\dfrac{base}{perpendicular} $}\\\\\\\large \text{$\sec \theta=\dfrac{hypotenuse}{base} $}\\\\\\\large \text{$cosec \ \theta=\dfrac{hypotenuse}{perpendicular} $}

Now some important identities are :

\large \text{$1. \ \sin^2 \theta+\cos^2 \theta=1$}\\\\\\\large \text{It can be also written as}\\\\\\\large \text{$\sin^2 \theta=1-\cos^2 \theta$}\\\\\\\large \text{$\cos^2 \theta=1-\sin^2 \theta$}\\\\\\\large \text{$2. \ \sec^2 \theta-\tan^2 \theta=1$}\\\\\\\large \text{It also can be also written as}\\\\\\\large \text{$\sec^2 \theta=1+\tan^2 \theta$}\\\\\\\large \text{$\tan^2 \theta=\sec^2 \theta-1$}

\large \text{$3. \ cosec^2 \theta-\cot^2 \theta=1$}\\\\\\\large \text{It also can be written as }\\\\\\\large \text{$cosec^2 \theta=1+\cot^2 \theta$}\\\\\\\large \text{$\cot^2 \theta=cosec^2 \theta-1$}

\large \text{$4. \ \tan \theta=\dfrac{\sin \theta}{\cos \theta} $}\\\\\\\large \text{$5. \ \cot \theta=\dfrac{\cos \theta}{\sin \theta} $}

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