Question

write all the trigonometric ratios in terms of sec A​

Answer 1

Answer:

this question answer is photograph.

Answer 2

Step-by-step explanation:

secA=

cosA

1

⇒cosA=

secA

1

sin

2

A+cos

2

A=1⇒sin

2

A=1−

sec

2

A

1

⇒sinA±

1−

sec

2

A

1

tanA=

sec

2

A−1

cotA=

tanA

1

=

sec

2

A−1

1

cscA=

sinA

1

=±

sec

2

A−1

sec

2

A