Math, asked by goelakshat08, 1 month ago

Write all the trigonometric ratios in the form of SinA.

Answers

Answered by ruchikhanakmitpaoh4p
0

Answer:

there you go :-  

cos a = square root of (1- square of sin a)  

tan = sin a / cos a = sin a/(square root of (1- square of sin a))  

cosec a = 1/sin a  

sec a = 1/cos a = 1/(square root of (1- square of sin a))  

cot a = cos a /sin a = (square root of (1- square of sin a))/sin a

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