Question

Write an 8086 Assembly language program that asks the user to input a single
hexadecimal number. The program will display equivalent binary or decimal value upon user
input selection 'B' for binary conversion and 'D' for decimal conversion.
Note: Binary and decimal conversion codes will be implemented as procedures and will be
called in the main procedure.
Sample Output:
Enter a character? F
Input 'B' for Binary Conversion and 'D' for decimal Conversion? B
The equivalent binary number for 'F' is 1111​

Answer 1

Answer:

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Explanation:

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Answer 2

ORG 100H  

SECTION .DATA  

PRO1 DB 0DH, 0AH, 0DH, 0AH, "INPUT A SIGNED BASE-10 INTEGER: $"  

PRO2 DB 0DH, 0AH, "YOUR NUMBER IN BINARY IS: $"  

PRO3 DB 0DH, 0AH, "PRETTY SURE THAT WASN'T A NUMBER. PLEASE ENTER A NUMBER VALUE: $"  

PRO4 DB 0DH, 0AH, "YOUR NUMBER IN OCTAL IS: $"  

SECTION .TEXT  

START:  

  MOV AH, 9; print input pro

  MOV DX, PRO1  

  INT 21H  

  MOV BX, 0; take input  

  MOV AH, 1  

  INT 21H  

DecIn:  

  CMP AL, 0DH; compare input to carriage return; check if user is finished or not

  JE DecOut; if yes, display the pro  

  CMP AL, '0'; compare to '0'  

  JG IsDigit; jump to IsDigit to confirm whether it is a number  

  JL NanError; if below 0, print error pro and start again  

IsDigit:  

  CMP AL, '9’; confirms digit value  

  JL BinCov; if digit, convert it to binary  

  JG NanError; if not, print an error message 'not a number'  

BinCov:  

  AND AX,000FH; convert it from ascii to base 10 value  

  PUSH AX;  save it on stack  

  MOV AX,10; set up to value to multiply bx by 10  

  IMUL BX; dx:ax = bx*10  

  POP BX; saved value in bx  

  ADD BX, AX; bx = old bx*10 + new digit  

  MOV AH,1; input char function  

  INT 21H; read next character  

  JMP DecIn; loop until false  

NanError:  

  MOV AH, 9; print error message  

  MOV DX, PRO3  

  INT 21H  

  JMP START; go back to the beginning  

DecOut:  

  MOV AH, 9; output the signed decimal value  

  MOV DX, PRO2  

  INT 21H  

  MOV CX, 16  

TOP:

  ROL BX,1; shift msb into cf

  JC ONE; CF = 1?  

  MOV DL,'0’; no, set up to print a 0  

  JMP PRINT; now print  

ONE:

  MOV DL,'1’; printing a 1  

PRINT:

  MOV AH,2; print char fcn  

  INT 21H; print it  

  LOOP TOP; loop until done  

  MOV AH, 2; print decimal value in bx  

  MOV DL, BL  

  INT 21H  

 JMP EXIT  

EXIT:  

  MOV AH,04CH; dos function: exit  

  MOV AL,0; exit code  

  INT 21H; call dos, exit