write an A.P those first term is a and the common difference d.
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hi mates her the answer
Step-by-step explanation:
the value of an is 11
the sum of first n terms of AP is
Sn=n/2 {2a+(n-1)d}
where, a is first term and d is common difference.
It is given that the first term is 8 it and the the common difference is 20. the sum of n terms is
Sn=n/2{2(8)+(n-1)20}
Sn=n/2 {16+20n-20}
Sn=n/2{20n-4}
Sn=n(10n-2)
the first term of another A.P is -30 and common difference is 8 the sum of 2n terms is
S2n =2n/2 {2(-30)+(2n-1)8}
S2n =n(-60+16n-8)
S2n =n(16n-68)
it is given that sum of n terms of another A.P
n(10n-2)=n(16n-68)
10n-2=16n-68
-2+68=16n-10n
66=6n
11=n
therefore the value of n is 11
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