Question

write an A.P whose a=-3 , d=4​

Answer 1

Given :

• First Term of AP(a) = -3
• Common Difference(d) = 4

To FinD :

The AP.

Solution :

Analysis :

We here have to find the numbers in this Arithmetic Progression. By using the required formula and substituting the required values we can find the AP.

Required Formula :

aₙ = a + (n - 1)d

where,

• aₙ = Respective term
• a = First Term
• n = The term
• d = common difference

Explanation :

Second Term of the AP :

We know that if we are given the first term and the common difference and is asked to find the AP then our required formula is,

aₙ = a + (n - 1)d

where,

• aₙ = a₂
• a = -3
• n = 2
• d = 4

By using the required formula and substituting the required values,

⇒ aₙ = a + (n - 1)d

⇒ a₂ = -3 + (2 - 1)4

⇒ a₂ = -3 + (1)4

⇒ a₂ = -3 + 1 × 4

⇒ a₂ = -3 + 4

⇒ a₂ = 1

∴ a₂ = 1.

Third Term of the AP :

We know that if we are given the first term and the common difference and is asked to find the AP then our required formula is,

aₙ = a + (n - 1)d

where,

• aₙ = a₃
• a = -3
• n = 3
• d = 4

By using the required formula and substituting the required values,

⇒ aₙ = a + (n - 1)d

⇒ a₃ = -3 + (3 - 1)4

⇒ a₃ = -3 + (2)4

⇒ a₃ = -3 + 2 × 4

⇒ a₃ = -3 + 8

⇒ a₃ = 5

∴ a₃ = 5.

Fourth Term of the AP :

We know that if we are given the first term and the common difference and is asked to find the AP then our required formula is,

aₙ = a + (n - 1)d

where,

• aₙ = a₄
• a = -3
• n = 4
• d = 4

By using the required formula and substituting the require values,

⇒ aₙ = a + (n - 1)d

⇒ a₄ = -3 + (4 - 1)4

⇒ a₄ = -3 + (3)4

⇒ a₄ = -3 + 3 × 4

⇒ a₄ = -3 + 12

⇒ a₄ = 9

∴ a₄ = 9.

The AP is -3, 1, 4, 9,...... so on.