Question

write an A.P whose first term a= 6 and common difference d= -3

Answer 1

Question:

Write an A.P whose first term a= 6 and common difference d= -3

Given:

• First term, a=6
• Common difference, d=-3

To Find:

• Arithmetic Progression

Solution:

We know that if a is first term and d is common difference, then the arithmetic Progression is

---› a, a+d, a+2d, a+3d, …

Here, a= 6 and d= -3

So,

---› $\mathsf{a=6}$

---› $\mathsf{a+d=6+(-3)=3}$

---› $\mathsf{a+2d=6+2(-3)= 6-6=0}$

---› $\mathsf{a+3d=6+3(-3)=6-9=-3}$

So, the arithmetic progression is 6, 3, 0, -3, …

More to know:

• A sequence is an arrangement of numbers or object in a definite order.
• A sequence ${a}_{1},{a}_{2},{a}_{3},..,{a}_{n}$ is called an arithmetic progression, if there exists a constant d such that

${a}_{2}-{a}_{1}=d$

Answer 2

Answer:

Given:

First term, a=6

Common difference, d=-3

To Find:

Arithmetic Progression

Solution:

We know that if a is first term and d is common difference, then the arithmetic Progression is

---› a, a+d, a+2d, a+3d, …

Here, a= 6 and d= -3

So,

--› a=6

a=6

---› a+d=6+(-3)=3

a+d=6+(−3)=3

---› a+2d=6+2(-3)= 6-6=0 a+2d=6+2(−3)=6−6=0

---› a+3d=6+3(-3)=6-9=-3

a+3d=6+3(−3)=6−9=−3

So, the arithmetic progression is 6, 3, 0, -3, …

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