Question

write an A.P whose first term is -1.25- and common difference is 0​

Answer 1

$there \: \: cannot \: \: be \: \: \: any \: \: a.p$

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Answer 2

Answer:

required AP is -1.25,-1.25,-1.25,-1.25,...

Step-by-step explanation:

a= -1.25

d= 0

first term= -1.25

second term= -1.25+0= -1.25

third term= -1.25+0= -1.25 and so on...

hence the required AP is -1.25,-1.25,-1.25,-1.25,...