Question

Write an A.P. whose first term is 10 and common difference is 5 ​

Answer 1

Step-by-step explanation:

let a1=10 and d=5

therefore,

a2=a1+d=10+5=15

a3=a2+d=15+5=20

a4=a3+d=20+5=25

Hence, The A.P. will be 10,15,20,25,......

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Answer 2

10, 15, 20, 25, 30, 35... and so on is an AP with the first term as 10 and the common difference as 5.

Step-by-Step Explanation:

Arithmetic progression is a progression in which every term after the first term (a) is obtained by adding a constant value, called the common difference (d). So, to find the nth term of an arithmetic progression, we use$a_{n} = a +(n-1)d$, where $a_{1}$ is the first term,  $a_{2}$ is the second term, and so on.

According to question,

d= 5 and a= 10

∴ The $a_{2}$ term= $a_{2} 10 + (2-1) 5$

⇒ $a_{2}= 15$

And, similarly,

$a_{3} = 10 + (3-1) 5= 20\\a_{4}= 10 + (4-1) 5= 25\\a_{5}= 10 + (5-1) 5= 30\\a_{6}= 10 + (6-1) 5= 35$  and so on.