Question

write an a. p whose first term is 10 and common difference is 3​

Answer 1

Answer:

here is your ans.

hope it helped

Answer 2

★GIVEN★

• First term of AP = 10.
• Common Difference = 3.

★To Find★

The AP.

★SOLUTION★

We know that,

$\large{\green{\underline{\boxed{\bf{a_{n}=a+(n-1)d}}}}}$

where,

• a is the first term
• n is the respective term
• d is the common difference

$\large{\green{\underline{\underline{\sf{1)\:The\:Second\:Term\::-}}}}}$

$\large\boxed{\bf{a_{n}=a+(n-1)d}}$

where,

• a = 10
• n = 2
• d = 3

Putting the values,

$\large\implies{\sf{a_{n}=a+(n-1)d}}$

$\large\implies{\sf{a_{2}=10+(2-1)\times3}}$

$\large\implies{\sf{a_{2}=10+1\times3}}$

$\large\implies{\sf{a_{2}=10+3}}$

$\large\therefore\boxed{\bf{a_{2}=13}}$

$\large{\green{\underline{\underline{\sf{2)\:The\:Third\:Term\::-}}}}}$

$\large\boxed{\bf{a_{n}=a+(n-1)d}}$

where,

• a = 10
• n = 3
• d = 3

Putting the values,

$\large\implies{\sf{a_{n}=a+(n-1)d}}$

$\large\implies{\sf{a_{3}=10+(3-1)\times3}}$

$\large\implies{\sf{a_{3}=10+2\times3}}$

$\large\implies{\sf{a_{3}=10+6}}$

$\large\therefore\boxed{\bf{a_{3}=16}}$

$\large{\green{\underline{\underline{\sf{The\:Fourth\:Term\::-}}}}}$

$\large\boxed{\bf{a_{n}=a+(n-1)d}}$

where,

• a = 10
• n = 4
• d = 3

Putting the values,

$\large\implies{\sf{a_{n}=a+(n-1)d}}$

$\large\implies{\sf{a_{4}=10+(4-1)\times3}}$

$\large\implies{\sf{a_{4}=10+3\times3}}$

$\large\implies{\sf{a_{4}=10+9}}$

$\large\therefore\boxed{\bf{a_{4}=19}}$

Like this it will go on.

$\large{\green{\underline{\boxed{\therefore{\bf{The\:AP\:is\:10, 13,16,19,.......}}}}}}$