Math, asked by sachinsinghm504, 8 months ago

Write an A.P. whose first term is a and common difference is d in each of the following.​

Answers

Answered by Anonymous
3

Answer:

(1) a = 10, d = 5

First term = a = 10

Second term = a + d = 10 + 5 = 15

Third term = a + 2d = 10 + 10 = 20

and so on...

Hence, the required A.P. is 10, 15, 20, 25, ...

(2) a = –3, d = 0

First term = a = –3

Second term = a + d = –3 + 0 = –3

Third term = a + 2d = –3 + 0 = –3

and so on...

Hence, the required A.P. is –3, –3, –3, ...

(3) a = –7, d = 12

First term = a = –7

Second term = a + d = −7+12=−132

Third term = a + 2d = –7 + 1 = –6

and so on...

Hence, the required A.P. is –7, –132, –6, ...

(4) a = –1.25, d = 3

First term = a = –1.25

Second term = a + d = –1.25 + 3 = 1.75

Third term = a + 2d = –1.25 + 6 = 4.75

and so on...

Hence, the required A.P. is –1.25, 1.75, 4.75, ...

(5) a = 6, d = –3

First term = a = 6

Second term = a + d = 6 – 3 = 3

Third term = a + 2d = 6 – 6 = 0

and so on...

Hence, the required A.P. is 6, 3, 0, ...

(6) a = 19, d = –4

First term = a = 19

Second term = a + d = 19 – 4 = 15

Third term = a + 2d = 19 – 8 = 11

and so on...

Hence, the required A.P. is 19, 15, 11, ...

Step-by-step explanation:

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