Question

write an A.P. whose first term is a and common difference is d. a= -3, d=0 .​

Answer 1

Answer:

First term = a = 10

Second term = 18 + d = 10+ 10 = 20

Third term = 20 + d = 20 + 10 = 30

Fourth term = 30 + d = 30 + 10 = 40

Hence, first four terms of the given A .P. are 10, 20, 30, 40.

Explanation:

by S.KANNAN

Answer 2

Answer:

-3, -3, -3 , ...... are the required A.P

Explanation:

The first term is " a " and the common difference is d.

And also given that, first term a = -3 and common difference d = 0.

• A series of numbers called an arithmetic progression or arithmetic sequence has a constant difference between the terms.

• For example, 2, 4, 6 ....12 are in A.P.

So, from the question we have the first term of an A.P is -3.

• General form of an A.P , a , a + d , a + 2d , a + 3d .........

Therefore, the second term is, a + d

Third term = a + 2d

Fourth term  = a + 3d

Therefore, a + d = -3 + 0 = -3, a + 2d = -3 + 0 = -3 , a + 3d = -3

so, second term is -3 , third term is -3 , fourth term is -3.

Final answer:

Hence, -3, -3, -3 , ...... are the required A.P

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